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-2m^2-26m-80=0
a = -2; b = -26; c = -80;
Δ = b2-4ac
Δ = -262-4·(-2)·(-80)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36}=6$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-6}{2*-2}=\frac{20}{-4} =-5 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+6}{2*-2}=\frac{32}{-4} =-8 $
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